3y^4-(4y^4+3)=

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Solution for 3y^4-(4y^4+3)= equation:


Simplifying
3y4 + -1(4y4 + 3) = 0

Reorder the terms:
3y4 + -1(3 + 4y4) = 0
3y4 + (3 * -1 + 4y4 * -1) = 0
3y4 + (-3 + -4y4) = 0

Reorder the terms:
-3 + 3y4 + -4y4 = 0

Combine like terms: 3y4 + -4y4 = -1y4
-3 + -1y4 = 0

Solving
-3 + -1y4 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1y4 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1y4 = 0 + 3
-1y4 = 0 + 3

Combine like terms: 0 + 3 = 3
-1y4 = 3

Divide each side by '-1'.
y4 = -3

Simplifying
y4 = -3

Reorder the terms:
3 + y4 = -3 + 3

Combine like terms: -3 + 3 = 0
3 + y4 = 0

The solution to this equation could not be determined.

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